$E=mc^2$
$E=mc^2$ #1cancel(kPa) * 760 torr/(101.325cancel(kPa)) = 7.50061683 torr#
You can easily link these two units by using atmospheres, or atm, as a starting point.
You know that 1 atm is equivalent to 760 torr. LIkewise, 1 atm is equivalent to 101.325 kPa, so the conversion factor that takes from torr to kPa will look like this
#760 torr/(1cancel(atm)) * (1cancel(atm))/101.325 kPa = 760 torr/101.325 kPa#
An heres your conversion factor #-># 760 torr are equivalent to 101.325 kPa, which means that
#1cancel(torr) * 101.325 kPa/(760cancel(torr)) = 0.133322368 kPa#
and
#1cancel(kPa) * 760 torr/(101.325cancel(kPa)) = 7.50061683 torr#
$E=mc^2$
