Matt And Ming Are Selling Fruit For A School Fundraiser

What is this formula? 3

I don't understand this math problem

Matt and Ming sell fruit for a small fundraiser. Customers can buy small crates of oranges and large crates of pebbles. Matt sold 3 small crates of oranges and 14 large crates of pebbles for a total of 3 203. Ming sold 11 small crates of stone and 11 large crates of stone in one big crate for a total of 20 220.

I tried 14x + 25y = 423.

does not work.

what I have to do?

S small box value, L large cell value, then:

Mat: 3S + 14L = 203 (a)

Sun: 11S + 11L = 220 (b)

I need a system of equations for S and L to solve.

Time 11 for Equation (a), Time 3 for Equation (b) I get:

33S + 154 L = 2233 (c)

33 S + 33 L = 660 (days)

Take (c) (d) I receive:

121 L = 1573 => L = 1573/121 = 13 USD per large box

By converting L = 13 to the equation (a) to find S, I get:

3S + 14 (13) = 203 => 3S = 203 182 = 21 => S = 21/3 = 7 لیے for a small box.

Matt And Ming Are Selling Fruit For A School Fundraiser

You need 2 equations. First, we need to translate from English to Math:
Matt sold 3 small crates of oranges and 14 large crates of oranges for a total of 3 203.
3 (small orange square) + 14 (large orange square) = 203.
[Equation 1] 3x + 14y = 203.
(Hint: Note that x is the value of the small box and y is the value of the large box and the answer is;)
Ming sold 11 small crates of stone and 11 large crates of stone for a total of 2 220.
11 (small orange square) + 11 (large orange square) = 220.
[Equation 2] 11x + 11y = 220.
Solve the equation 2 for x: 11x + 11y = 220.
Divide by 11 x + y = 20.
I think you need to use the equation at the same time. Leave a small square = x.
And give the big box = y.
Matt sold 3 small boxes (3x) and 14 large boxes (14 years) for 3 203. So the equation is 3x + 14y = 203
Now draw another equation and solve the two together. Ming is selling 11 small (11x) and 11 large (11 years) boxes at $ 220. Therefore, 11x + 11y = 220
3x + 14 years = 203 1
11x + 11y = 220 2
Multiply 1 by 11.
33x + 154y = 2260
Now multiply number 2 by 3.
33x + 33y = 660
Now subtract 33x + 33y = 660 from 33x + 154y = 2260
33x + 154y = 2260
33x + 33y = 660
0x + 121y = 1600
y = 1600/121
=. 13.22, so the price of each large box is the same.
Now convert to the original equation and get the value of x.
33x + 33x13.22 = 660
33x + 436.26 = 660
33x = 227.74
x = $ 6.90 are small squares.
Mat 203 = 3x + 14y
Sunday 220 = 11x + 11 years
Solve Ming for X. in regards to
11x = 220 11 years
x = 20 years
Put it in the mat equation.
3 (20 years) + 14 years = 203
603a + 14a = 203
11 years = 143
y = 13
Return this value to the equation you found for x.
x = 20 (13)
x = 7
Small box $ 7
Big box 13