Derivata Di Ln 2x
What is the derivative of ln
2lnx / x
In practice, the first derivation of enza and then multiple internal derivations that 1 / x oppress the following derivative treatment:
Derived from lnx * lnx and fai otto ed ottieni:
1 / x * lnx + 1 / x * lnx = 1 / x (2lnx) = 2lnx / x
Enter and modify the result is the same
2lnx / x
In general, f (x) n n * f (x) [(n1)] * derivative of f (x).
In this case, f  is sufficient ln (x), and f ¨ 1 / x, the quotient derivative ¨ 2 * ln x / x
Dln 2x = (2lnx) / x
D = (2ln x) * Dln x
Dln x = 1 / x
To spread the Regula compound in derivatizion per le enzioni:
D g (f (x)) = g (t) * f (x)
Pigeon t = f (x)
In this case g (f (x)) ¨ ln 2 (x) and f (x) ¨ ln (x),
Derivative perciò 1
2 * ln (x) * 1 / x
