A Local Eye Clinic Has Two Doctors
Help for statistical probability? 3
There are two doctors in a local eye clinic. Dr. Kutallot recommends freezing 60% of the time and corrective surgery 40% of the time. Dr. Lenzi recommends freezing 70% of the time and working 30% of the time. 60% of the patients were supported by the doctor. Lenzie behaves. Both doctors did not treat the patient. If a patient is randomly selected, how likely is it that surgery will be recommended?
Can anyone explain to me?
This has been answered.
18%
3.4%
35%
58%
70%
Any help is greatly appreciated. :)
Hahaha Dr. Clot.
The law of absolute truth
dr L ............. + dr K
The answer is 34%
Here you go:
100% (total) are sick (by definition)
Dr. L. obtained 60% and recommended surgery for 30% * tse *
This 60% * 30% = 18% of all doctor L * & * patients are treated for surgery
Dr. K. saw 40% of the patients and recommended surgery for 40% * tse *.
This 40% * 40% = 16% of all doctors * and * patients are treated for surgery.
18% + 16% = 34%
